JSONP跨站ajax简单事例

追影

1. html:
   
2. <script src="/public/js/jquery.js" type="text/javascript"></script>
   
3. <script>
   
4. $.getJSON("http://192.168.1.102/index.php?app=home&mod=Public&act=ajax_check_login&username=%E7%AE%A1%E7%90%86%E5%91%98&password=87127547&jsoncallback=?", function(json){});
   
5. 
   
6. function callback(json){
   
7. alert(json.result);
   
8. }
   
9. </script>
   
10. 
    
11. php:
    
12. 
    
13. //AJAX验证登陆
    
14.   public function ajax_check_login() {
    
15.   
    
16.   // 数据检查
    
17.   if ( empty($_REQUEST['password']) ) {
    
18.    echo '0';
    
19.    exit;
    
20.   }
    
21.        $is_logged = false;
    
22.   if (isset($_REQUEST['email'])) {
    
23.    $is_logged = service('Passport')->loginAdmin($_REQUEST['email'], $_REQUEST['password']);
    
24.   }else if ( isset($_REQUEST['username'])) {
    
25.    $is_logged = service('Passport')->loginAdmin(urldecode($_REQUEST['username']), $_REQUEST['password']);
    
26.   }else if ( isset($_REQUEST['mobile'])) {
    
27.    $is_logged = service('Passport')->loginAdmin($_REQUEST['mobile'], $_REQUEST['password']);
    
28.   }
    
29.   
    
30.   $ret = ($is_logged == false?0:1);
    
31.   $arr = array('result'=>$ret);
    
32.   
    
33. $callback= isset($_GET['callback'])?isset($_GET['callback']):'callback';
    
34. $json = json_encode($arr);
    
35. echo $callback.'('.$json.')';
    
36. }

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